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How do you calculate the volume of a gas under pressure?
For example, if you want to calculate the volume of 40 moles of a gas under a pressure of 1013 hPa and at a temperature of 250 K, the result will be equal to: V = nRT/p = 40 * 8.3144598 * 250 / 101300 = 0.82 m³ .
How do you find volume with mol and pressure?
First, let’s review the ideal gas law, PV = nRT. In this equation, ‘P’ is the pressure in atmospheres, ‘V’ is the volume in liters, ‘n’ is the number of particles in moles, ‘T’ is the temperature in Kelvin and ‘R’ is the ideal gas constant (0.0821 liter atmospheres per moles Kelvin).
What is the pressure of a 5 liter per mole ideal gas at temperature 27 C?
What is the pressure of a 5 liter/mole ideal gas at temperature 27oC? Explanation: PV = nRT, => P*5 = 0.0821*300, => P = 5.3 atm. 7.
What is the volume of 1.00 mole of any gas at STP?
22.41 L/mol
What is the volume of 1 mole of an ideal gas at STP (Standard Temperature and Pressure = 0 °C, 1 atm)? So, the volume of an ideal gas is 22.41 L/mol at STP. This, 22.4 L, is probably the most remembered and least useful number in chemistry.
How do you find moles of gas from volume?
Multiply the volume and pressure and divide the product by the temperature and the molar gas constant to calculate moles of the hydrogen gas. In the example, the amount of hydrogen is 202,650 x 0.025 / 293.15 x 8.314472 = 2.078 moles.
What is the volume of one mole of hydrogen gas at STP?
22.4 L
Avogadro’s law specifies that the volume of one mole of any gas at STP is 22.4 L.
What is the volume of 1 mole of gas at NTP?
The standard molar volume for an ideal gas is taken to be 22.414 L/mol at STP. According to Avogadro’s hypothesis one gram mole of a gas at NTP occupies 22.4 L.
What volume is occupied by 2.0 mol of a gas at STP?
David G. Assuming that the gas is at standard temperature and pressure (STP), one mole of any gas occupies 22.4 L . This means the number of moles of O2 is 222.4=0.089 mol .